` 구현 문제…?
더 깔끔한 방법이 있을 것 같지만 잘 생각나지 않아 일일이 계산하는 방식을 택함…
- for문 3개를 써서 win + lose + draw 가 20일 때 조건 만족
- 확률과 경우의 수 계산
- 확률 : $ W^{win} * L^{lose} * D^{draw} $
- 경우의 수 : $ 20! \over (win! * lose! * draw!) $
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import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class B14613 {
static double W,L,D;
static double[] arr = new double[5];
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringBuilder sb = new StringBuilder();
StringTokenizer st = new StringTokenizer(br.readLine());
W = Double.parseDouble(st.nextToken());
L = Double.parseDouble(st.nextToken());
D = Double.parseDouble(st.nextToken());
for (int win = 0; win <= 20; win++){
for (int lose = 0; lose <= 20; lose++){
for (int draw = 0; draw <= 20; draw++){
if (win + lose + draw == 20){
int score = 2000 + win * 50 - lose * 50;
double pro = Math.pow(W, win * 1.0) * Math.pow(L, lose * 1.0) * Math.pow(D, draw * 1.0) * factorial(20)
/ factorial(win) / factorial(draw) / factorial(lose);
if (score >= 1000 && score <= 1499){
arr[0] += pro;
}else if (score >= 1500 && score <= 1999){
arr[1] += pro;
}else if (score >= 2000 && score <= 2499){
arr[2]+= pro;
}else if (score >= 2500 && score <= 2999){
arr[3] += pro;
}else if (score >= 3000 && score <= 3499){
arr[4] += pro;
}
}
}
}
}
for(double x : arr) {
sb.append(String.format("%.8f", x)).append("\n");
}
System.out.println(sb);
}
private static double factorial(int x)
{
if (x<=1) return 1.0;
return x*factorial(x-1);
}
}
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